Reply to "Rolling Tire Characteristics"

AdminMember

Duane,

I know it seems like the effective radius being the axle's height to the ground should be the right answer, but it's not. The tire is not a circle anymore, so the effective radius is going to be dependent on what new deformed shape it takes, not simply the axle's height to the ground.

To give you a simple example to help convince you, consider a wheel made of a flexible hoop with a 1-foot radius and spokes replaced by strings. You could squash this hoop down into some odd shape with the axle only a couple inches from the ground. But the effective radius would still be 1 foot because you didn't change the perimeter of the wheel by squashing it down. In one revolution you will still travel 2*pi feet.

7/9/088:31 PM

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