Reply to "Jones Counter Redesign"

AdminMember

Neville,

I'm confused how this would work. Let's say a rider leaves the correct course at point A, where the rim reading was 0, and for simplicity's sake let's say he rides off course for only .1 revolutions. If he turns his bike around at this point, won't his rim reading be .2 when he gets back to point A? It needs to be back to 0 at point A, right?

10/15/073:37 AM

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